(c) Given, $y = ae^{mx} + be^{- mx}$ $\Rightarrow$ $\frac{dy}{dx} = mae^{mx} - m\ be^{- mx}$ $\Rightarrow$ $\frac{d^{2}y}{dx^{2}} = m^{2}ae^{mx} + m^{2}be^{- mx} = m^{2}y$ $\Rightarrow$ $\frac{d^{2}y}{dx^{2}} - m^{2}y = 0$
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Ph.D. in Physics with 19+ years of teaching experience.