(b) Given, $\frac{dy}{dx} = - \frac{1 + y + x^{2}y}{x + x^{3}}$ $\Rightarrow$ $\frac{dy}{dx} + \frac{y}{x} = - \frac{1}{x(1 + x^{2})}$ $\therefore$ $IF = e^{\int_{}^{}{\frac{1}{x}\ dx}} = x$
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Ph.D. in Physics with 19+ years of teaching experience.