Q. The solution of differential equation $(\sin{x + \cos{x)dy + (\cos{x - \sin{x)dx = 0}}}}$ is

A) $e^{x}(\sin{x + \cos{x) + c = 0}}$
B) $e^{y}(\sin{x + \cos{x) = c}}$
C) $e^{y}(\cos{x - \sin{x) = c}}$
D) $e^{x}(\sin{x - \cos{x + x) = c}}$
Explanation

(b)
$\frac{dy}{dx} = - \left( \frac{\cos{x - \sin x}}{\sin{x + \cos x}} \right)$
$\Rightarrow dy = - \left( \frac{\cos{x - \sin x}}{\sin{x + \cos x}} \right)dx$
On integrating both sides, we get
$y = - \log{(\sin{x + \cos{x) + \log c}}}$
$\Rightarrow y = \log\left( \ \frac{c}{\sin{x + \cos x}}\ \right)$
$\Rightarrow e^{y} = \frac{c}{\sin{x + \cos x}}$
$\Rightarrow e^{y}\left( \sin{x + \cos x} \right) = c\$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.