(b)
Since, given vectors are perpendicular.
$\therefore\left( 3\widehat{\dot{\mathbf{i}}} - 2\widehat{\dot{\mathbf{j}}} - 5\widehat{\mathbf{k}} \right) \bullet \left( 6\widehat{\dot{\mathbf{i}}} - \widehat{\dot{\mathbf{j}}} + c\widehat{\mathbf{k}} \right) = 0$
$\Longrightarrow 18 + 2 - 5c = 0\ \Longrightarrow c = 4$