Q. Let $P,Q,R$ and $S$ be the points on the plane with position vectors $- 2\widehat{\dot{\mathbf{i}}} - \widehat{\dot{\mathbf{j}}}\ ,4\widehat{\dot{\mathbf{i}}},3\widehat{\dot{\mathbf{i}}} + 3\widehat{\dot{\mathbf{j}}}$ and $- 3\widehat{\dot{\mathbf{i}}} + 2\widehat{\dot{\mathbf{j}}}$ respectively. The quadrilateral $PQRS$ must be

A) Parallelogram, which is neither a rhombus nor a rectangle
B) Square
C) Rectangle, but not a square
D) Rhombus, but not a square
Explanation

(a)
$\overrightarrow{\mathbf{PQ}} = 6\widehat{\dot{\mathbf{i}}} + \widehat{\dot{\mathbf{j}}}$l
$\overrightarrow{\mathbf{QR}} = - \widehat{\dot{\mathbf{i}}} + 3\widehat{\dot{\mathbf{j}}}$
$\overrightarrow{\mathbf{RS}} = - 6\widehat{\dot{\mathbf{i}}} - \widehat{\dot{\mathbf{j}}}$
$\overrightarrow{\mathbf{SP}} = \widehat{\dot{\mathbf{i}}} - 3\widehat{\dot{\mathbf{j}}}$
$\left| \overrightarrow{\mathbf{PQ}} \right| = \sqrt{37} = \left| \overrightarrow{\mathbf{RS}} \right|$
$\left| \overrightarrow{\mathbf{QR}} \right| = \sqrt{10} = \left| \overrightarrow{\mathbf{SP}} \right|$
$\overrightarrow{\mathbf{PQ}} \bullet \overrightarrow{\mathbf{QR}} = - 6 + 3 = - 3 \neq 0$
$\overrightarrow{\mathbf{PQ}} =$ is not parallel to $\overrightarrow{\mathbf{RS}}$ and their magnitude are equal.
$\Longrightarrow$ Quadrilateral $PQRS$ must be a parallelogram, which is neither a rhombus nor a rectangle.

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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