Q. The equation of the plane perpendicular to the line $\frac{x - 1}{1} = \frac{y - 2}{- 1} = \frac{z + 1}{2}\ and\ passing\ through\ the\ point(2,3,1)\ is\$

A) $\overrightarrow{\mathbf{r}} \bullet \left( \widehat{\dot{\mathbf{i}}} + \widehat{\dot{\mathbf{j}}} + 2\widehat{\mathbf{k}} \right) = 1$
B) $\overrightarrow{\mathbf{r}} \bullet \left( \widehat{\dot{\mathbf{i}}} - \widehat{\dot{\mathbf{j}}} + 2\widehat{\mathbf{k}} \right) = 1$
C) $\overrightarrow{\mathbf{r}} \bullet \left( \widehat{\dot{\mathbf{i}}} - \widehat{\dot{\mathbf{j}}} + 2\widehat{\mathbf{k}} \right) = 7$
D) $\overrightarrow{\mathbf{r}} \bullet \left( \widehat{\dot{\mathbf{i}}} + \widehat{\dot{\mathbf{j}}} - 2\widehat{\mathbf{k}} \right) = 10$
Explanation

(b)
$The\ given\ line\ is\ parallel\ to\ the\ vector\ \overrightarrow{\mathbf{n}} = \widehat{\dot{\mathbf{i}}} - \widehat{\dot{\mathbf{j}}} + 2\widehat{\mathbf{k}}.The\ required\ plane\ passing\$
$through\ the\ point\ (2,\ 3,\ 1)ie,\ 2\widehat{\dot{\mathbf{i}}} + 3\widehat{\dot{\mathbf{j}}} + \widehat{\mathbf{k}}\ \ and\ is\ perpendicular\ to\ the\ vector$
$\ \overrightarrow{\mathbf{n}} = \widehat{\dot{\mathbf{i}}} - \widehat{\dot{\mathbf{j}}} + 2\widehat{\mathbf{k}}$
$\therefore Its\ equation\ is$
$\lbrack\left( \overrightarrow{\mathbf{r}} - \left( 2\widehat{\dot{\mathbf{i}}} + 3\widehat{\dot{\mathbf{j}}} + \widehat{\mathbf{k}} \right) \right\rbrack \bullet \left( \widehat{\dot{\mathbf{i}}} - \widehat{\dot{\mathbf{j}}} + 2\widehat{\mathbf{k}} \right) = 0$
$\Longrightarrow \overrightarrow{\mathbf{r}} \bullet \left( \widehat{\dot{\mathbf{i}}} - \widehat{\dot{\mathbf{j}}} + 2\widehat{\mathbf{k}} \right) = 1$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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