(b)
Given, $\overrightarrow{\mathbf{a}} \bullet \overrightarrow{\mathbf{b}} = - \left| \overrightarrow{\mathbf{a}} \right|\left| \overrightarrow{\mathbf{b}} \right|$
$\Longrightarrow \left| \overrightarrow{\mathbf{a}} \right|\left| \overrightarrow{\mathbf{b}} \right|\cos{\theta = - \left| \overrightarrow{\mathbf{a}} \right||\overrightarrow{\mathbf{b}}|}$
$\Longrightarrow \cos{\theta = - 1}$
$\Longrightarrow \theta = 180{^\circ}$