$\overrightarrow{\mathbf{AB}} imes \overrightarrow{\mathbf{AC}} = 2\widehat{\dot{\mathbf{i}}} - 4\widehat{\dot{\mathbf{j}}} + 4\widehat{\mathbf{k}},$ then the area of $\mathrm{\Delta}\ ABC$ is

Question

$\overrightarrow{\mathbf{AB}} 	imes \overrightarrow{\mathbf{AC}} = 2\widehat{\dot{\mathbf{i}}} - 4\widehat{\dot{\mathbf{j}}} + 4\widehat{\mathbf{k}},$ then the area of $\mathrm{\Delta}\ ABC$ is

Dr. Abubacker · Accepted Answer

(a)
$Area\ of\ \mathrm{\Delta}\ ABC = \frac{1}{2}\left| \overrightarrow{\mathbf{AB}} 	imes \overrightarrow{\mathbf{AC}} ight|$
$= \frac{1}{2}\sqrt{4 + 16 + 16} = 3\ sq\ units$

Q. $\overrightarrow{\mathbf{AB}} \times \overrightarrow{\mathbf{AC}} = 2\widehat{\dot{\mathbf{i}}} - 4\widehat{\dot{\mathbf{j}}} + 4\widehat{\mathbf{k}},$ then the area of $\mathrm{\Delta}\ ABC$ is

Explanation

Reviewed by Dr. Abubacker

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