(b)
Here, $\left| \overrightarrow{\mathbf{a}} \right| = \sqrt{1 + 1 + (4)^{2}} = 3\sqrt{2}$
$and\ \left| \overrightarrow{\mathbf{b\ }} \right| = \sqrt{1 + ( - 1)^{2} + (4)^{2}} = 3\sqrt{2}$
$\therefore\left| \overrightarrow{\mathbf{a}} \right| = \left| \overrightarrow{\mathbf{b}} \right|$
Now, $\left( \overrightarrow{\mathbf{a}} + \overrightarrow{\mathbf{b}} \right) \bullet \left( \overrightarrow{\mathbf{a}} \bullet \overrightarrow{\mathbf{b}} \right) = {|\overrightarrow{\mathbf{a}}|}^{2} - {|\overrightarrow{\mathbf{b}}|}^{2} = 0$
Hence, angle between them is $90{^\circ}$