Q. The projection of $\overrightarrow{\mathbf{a}} = 3\widehat{\dot{\mathbf{i}}} - \widehat{\dot{\mathbf{j}}} + 5\widehat{\mathbf{k}}$ on $\overrightarrow{\mathbf{b}} = 2\widehat{\dot{\mathbf{i}}} + 3\widehat{\dot{\mathbf{j}}} + \widehat{\mathbf{k}}$ is

A) $\frac{8}{\sqrt{35}}$
B) $\frac{9}{\sqrt{39}}$
C) $\frac{8}{\sqrt{14}}$
D) $\sqrt{14}$
Explanation

(c)
The projection of
$\overrightarrow{\mathbf{a}}\ on\ \overrightarrow{\mathbf{b}} = \frac{\overrightarrow{\mathbf{a}}\ \bullet \overrightarrow{\mathbf{b}}}{\left| \overrightarrow{\mathbf{b}} \right|}$
$= \frac{\left( 3\widehat{\dot{\mathbf{i}}} - \widehat{\dot{\mathbf{j}}} + 5\widehat{\mathbf{k}} \right) \bullet (2\widehat{\dot{\mathbf{i}}} + 3\widehat{\dot{\mathbf{j}}} + \widehat{\mathbf{k}})}{\sqrt{2^{2} + 3^{2} + 1^{2}}} = \frac{8}{\sqrt{14}}$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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