(c)
$\because\ \left( \overrightarrow{\mathbf{a}} \times \overrightarrow{\mathbf{b}} \right) \times \overrightarrow{\mathbf{c}} = \overrightarrow{\mathbf{a}} \times \left( \overrightarrow{\mathbf{b}} \times \overrightarrow{\mathbf{c}} \right)$
$\Longrightarrow \left( \overrightarrow{\mathbf{a}} \bullet \overrightarrow{\mathbf{c}} \right)\overrightarrow{\mathbf{b}} - \left( \overrightarrow{\mathbf{b}} \bullet \overrightarrow{\mathbf{c}} \right)\overrightarrow{\mathbf{a}} = \left( \overrightarrow{\mathbf{a}} \bullet \overrightarrow{\mathbf{c}} \right)\overrightarrow{\mathbf{b}} - \left( \overrightarrow{\mathbf{a}} \bullet \overrightarrow{\mathbf{b}} \right)\overrightarrow{\mathbf{c}}$
$\Longrightarrow \left( \overrightarrow{\mathbf{b}} \bullet \overrightarrow{\mathbf{c}} \right)\overrightarrow{\mathbf{a}} = \left( \overrightarrow{\mathbf{a}} \bullet \overrightarrow{\mathbf{b}} \right)\overrightarrow{\mathbf{c}}$
$\Longrightarrow \ \overrightarrow{\mathbf{a}}$ is parallel to $\overrightarrow{\mathbf{c}}$