(c)
Given vectors will be coplanar, if $\left| \begin{matrix}
–\lambda^{2} & 1 & 1 \\
1 & –\lambda^{2} & 1 \\
1 & 1 & - \lambda^{2}
\end{matrix} \right| = 0$
$\Longrightarrow \ \lambda^{6} - 3\lambda^{2} - 2 = 0$
$\Longrightarrow (1 + \lambda^{2})^{2}\left( \lambda^{2} - 2 \right) = 0 \Longrightarrow \lambda^{\ } = \pm \sqrt{2}$