Q. $\left( \overrightarrow{\mathbf{a}} \bullet \widehat{\dot{\mathbf{i}}} \right)\widehat{\dot{\mathbf{i}}} + \left( \overrightarrow{\mathbf{a}} \bullet \widehat{\dot{\mathbf{j}}} \right)\widehat{\dot{\mathbf{j}}} + (\overrightarrow{\mathbf{a}} \bullet \widehat{\mathbf{k}})\widehat{\mathbf{k}}$ is equal to

A) $\overrightarrow{\mathbf{a}}$
B) $2\ \overrightarrow{\mathbf{a}}$
C) $3\ \overrightarrow{\mathbf{a}}$
D) $\overrightarrow{\mathbf{0}}$
Explanation

(a)
Let $\overrightarrow{\mathbf{a}} = x\widehat{\dot{\mathbf{i}}} + y\widehat{\dot{\mathbf{j}}} + z\widehat{\mathbf{k}}$
$\therefore\ \left( \overrightarrow{\mathbf{a}} \bullet \widehat{\dot{\mathbf{i}}} \right)\widehat{\dot{\mathbf{i}}} = \left\lbrack \left( x\widehat{\dot{\mathbf{i}}} + y\widehat{\dot{\mathbf{j}}} + z\widehat{\mathbf{k}} \right) \bullet \widehat{\dot{\mathbf{i}}} \right\rbrack\widehat{\dot{\mathbf{i}}} = x\widehat{\dot{\mathbf{i}}}$
Similarly, $\left( \overrightarrow{\mathbf{a}} \bullet \widehat{\dot{\mathbf{j}}} \right)\widehat{\dot{\mathbf{i}}} = y\widehat{\dot{\mathbf{j}}},\left( \overrightarrow{\mathbf{a}} \bullet \widehat{\mathbf{k}} \right)z\widehat{\mathbf{k}}$
$\therefore\left( \overrightarrow{\mathbf{a}} \bullet \widehat{\dot{\mathbf{i}}} \right)\widehat{\dot{\mathbf{i}}} + \left( \overrightarrow{\mathbf{a}} \bullet \widehat{\dot{\mathbf{j}}} \right)\widehat{\dot{\mathbf{j}}} + \left( \overrightarrow{\mathbf{a}} \bullet \widehat{\mathbf{k}} \right)\widehat{\mathbf{k}} = x\widehat{\dot{\mathbf{i}}} + y\widehat{\dot{\mathbf{j}}} + z\widehat{\mathbf{k}} = \overrightarrow{\mathbf{a}}$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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