Q. $ABCD$ is a quadrilateral , $P,Q$ are the mid points of $\overrightarrow{\mathbf{BC}}$ and $\overrightarrow{\mathbf{AD}}$, then $\overrightarrow{\mathbf{AB}} + \overrightarrow{\mathbf{DC}}$ is equal to
A) $3\ \overrightarrow{\mathbf{QP}}$
B) $\overrightarrow{\mathbf{QP}}$
C) $4\overrightarrow{\mathbf{QP}}$
D) $2\overrightarrow{\mathbf{QP}}$
Explanation
(d)
$\because\ \overrightarrow{\mathbf{QP}}$ is parallel to $\overrightarrow{\mathbf{AB}}$ and $\overrightarrow{\mathbf{DC}}.$
$\therefore\ \overrightarrow{\mathbf{AB}} + \overrightarrow{\mathbf{DC}} = \overrightarrow{\mathbf{QP}} + \overrightarrow{\mathbf{QP}} = 2\overrightarrow{\mathbf{QP}}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.