Q. If $\left| \overrightarrow{\mathbf{a}} \right| = 5,\ |\overrightarrow{\mathbf{b}}| = 6$ and $\overrightarrow{\mathbf{a}} \bullet \overrightarrow{\mathbf{b}} = - 25,$ then $|\overrightarrow{\mathbf{a}} \times \overrightarrow{\mathbf{b}}|$ is equal to

A) 25
B) $6\sqrt{11}$
C) $11\sqrt{5}$
D) $5\sqrt{11}$
Explanation

(d)
$\left| \overrightarrow{\mathbf{a}} \times \overrightarrow{\mathbf{b}} \right|^{2} + \left( \overrightarrow{\mathbf{a}} \bullet \overrightarrow{\mathbf{b}} \right)^{2} = \left| \overrightarrow{\mathbf{a}} \right|^{2}\ \ |\overrightarrow{\mathbf{b}}|^{2}$
$\Longrightarrow |\overrightarrow{\mathbf{a}} \times \overrightarrow{\mathbf{b}}|^{2} = 25 \times 36 - (25)^{2}$
$= 25(36 - 25)$
$= 25 \times 11$
$\Longrightarrow |\overrightarrow{\mathbf{a}} \times \overrightarrow{\mathbf{b}}| = 5\sqrt{11}$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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