Q. If $C$ is the mid point of $AB$ and $P$ is any point outside $AB$, then
A) $\overrightarrow{\mathbf{PA}} + \overrightarrow{\mathbf{PB}} = \overrightarrow{\mathbf{PC}}$
B) $\overrightarrow{\mathbf{PA}} + \overrightarrow{\mathbf{PB}} + 2\overrightarrow{\mathbf{PC}} = \overrightarrow{0}$
C) $\overrightarrow{\mathbf{PA}} + \overrightarrow{\mathbf{PB}} - 2\overrightarrow{\mathbf{PC}} = \overrightarrow{0}$
D) $\overrightarrow{\mathbf{PA}} + \overrightarrow{\mathbf{PB}} + 2\overrightarrow{\mathbf{PC}} = \overrightarrow{0}$
Explanation
(c)
By the properties of midpoint theorem,
$\overrightarrow{\mathbf{PA}} + \overrightarrow{\mathbf{PB}} = 2\overrightarrow{\mathbf{PC}}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.