(a)
Let $\overrightarrow{\mathbf{OA}} = \widehat{\dot{\mathbf{i}}} + 2\widehat{\dot{\mathbf{j}}} + 3\widehat{\mathbf{k}}$ and $\overrightarrow{\mathbf{OB}} = 3\widehat{\dot{\mathbf{i}}} + 4\widehat{\dot{\mathbf{j}}} + 5\widehat{\mathbf{k}}$
$\therefore\ \overrightarrow{\mathbf{AB}} = 2\widehat{\dot{\mathbf{i}}} + 2\widehat{\dot{\mathbf{j}}} + 2\widehat{\mathbf{k}}$
$\therefore$ work don, $W = \overrightarrow{\mathbf{F}} \bullet \overrightarrow{\mathbf{AB}}$
$= \left( 2\widehat{\dot{\mathbf{i}}} - 3\widehat{\dot{\mathbf{j}}} + 2\widehat{\mathbf{k}} \right) \bullet \left( 2\widehat{\dot{\mathbf{i}}} + 2\widehat{\dot{\mathbf{j}}} + 2\widehat{\mathbf{k}} \right)$
$= 4 - 6 + 4 = 2$