(d)
$\because\overrightarrow{\mathbf{b}} \times \overrightarrow{\mathbf{c}} = \left| \begin{matrix}
\widehat{\dot{\mathbf{i}}} & \widehat{\dot{\mathbf{j}}} & \widehat{\mathbf{k}} \\
1 & 2 & - 5 \\
3 & 5 & - 1
\end{matrix} \right| = 23\widehat{\dot{\mathbf{i}}} - 14\widehat{\dot{\mathbf{j}}} - \widehat{\mathbf{k}}\$
$\therefore\overrightarrow{\mathbf{a}} \times \left( \overrightarrow{\mathbf{b}} \times \overrightarrow{\mathbf{c}} \right) = \left| \begin{matrix}
\widehat{\dot{\mathbf{i}}} & \widehat{\dot{\mathbf{j}}} & \widehat{\mathbf{k}} \\
2 & 3 & - 1 \\
23 & - 14 & - 1
\end{matrix} \right| = - 17\widehat{\dot{\mathbf{i}}} - 21\widehat{\dot{\mathbf{j}}} - 97\widehat{\mathbf{k}}\$