Q. If $\overrightarrow{\mathbf{a}}\mathbf{,}\overrightarrow{\mathbf{b}}\mathbf{,}\overrightarrow{\mathbf{c}}$ are vectors such that $\overrightarrow{\mathbf{c}}\mathbf{=}\overrightarrow{\mathbf{a}}\mathbf{+}\overrightarrow{\mathbf{b}}$ and $\overrightarrow{\mathbf{a}}\mathbf{\bullet}\overrightarrow{\mathbf{b}} = 0$, then

A) $a^{2} + b^{2} + c^{2} = 0$
B) $a^{2} - b^{2} = c^{2}$
C) $a^{2} + b^{2} = c^{2}$
D) $\overrightarrow{\mathbf{c}}\mathbf{=}\overrightarrow{\mathbf{a}}\mathbf{\times}\overrightarrow{\mathbf{b}}$
Explanation

The correct answer is Option C: $a^{2} + b^{2} = c^{2}$.

A detailed explanation for this question is being prepared.

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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