Q. The vectors $\overrightarrow{\mathbf{a}}(x) = \cos{x\ \widehat{\mathbf{i}} + (\sin{x)\widehat{\mathbf{j}}\ and\ \overrightarrow{\mathbf{b}}(x) = x\mathbf{\ }\widehat{\mathbf{i}} + \sin{x\ \widehat{\mathbf{j}}}}}$ are collinear for

A) Unique value of $x,0 < x < \frac{\pi}{6}$
B) Unique value of $x,\frac{\pi}{6} < x < \frac{\pi}{3}$
C) No value of $x$
D) Infinitely many values of $x,0 < x < \frac{\pi}{2}$
Explanation

(b)
For collinearity, ${\ cos}x\widehat{\mathbf{i}} + \sin{x\mathbf{\ }\widehat{\mathbf{j}} =}\lambda(x\widehat{\mathbf{i}} + \sin{x\ \widehat{\mathbf{j}}})$
$\Rightarrow \cos{x = x}$
Let $f(x) = \cos{x - x}$
$\Rightarrow f^{'}(x) = - \sin{x - 1 < 0}$
$f(x)$ is decreasing function and for $x \geq \frac{\pi}{3},f(x) < 0$ and for $\frac{\pi}{3} < x < \frac{\pi}{6},\ f(x) > 0$.
Hence, unique solution exist.

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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