Q. $\left( \overrightarrow{\mathbf{a}} - \overrightarrow{\mathbf{b}} \right) \bullet \{\left( \overrightarrow{\mathbf{b}} - \overrightarrow{\mathbf{c}} \right) \times \left( \overrightarrow{\mathbf{c}} - \overrightarrow{\mathbf{a}}\ \right)\}$ is equal to

A) $2\ \overrightarrow{\mathbf{a}} \bullet \overrightarrow{\mathbf{b}} \times \overrightarrow{\mathbf{c}}$
B) $\overrightarrow{\mathbf{a}} \bullet \overrightarrow{\mathbf{b}} \times \ \overrightarrow{\mathbf{c}}$
C) 0
D) $\overrightarrow{\mathbf{a}} \bullet \ \overrightarrow{\mathbf{b}}\$
Explanation

(c)
$\left( \overrightarrow{\mathbf{a}} - \overrightarrow{\mathbf{b}} \right) \bullet (\overrightarrow{\mathbf{b}} \times \overrightarrow{\mathbf{c}} - \overrightarrow{\mathbf{b}} \times \overrightarrow{\mathbf{a}} + \overrightarrow{\mathbf{c}} \times \overrightarrow{\mathbf{a}}$)
$= \overrightarrow{\mathbf{a}} \bullet \left( \overrightarrow{\mathbf{b}} \times \overrightarrow{\mathbf{c}} \right) - \overrightarrow{\mathbf{b}} \times \left( \overrightarrow{\mathbf{c}} \times \overrightarrow{\mathbf{a}} \right)$
$= \left\lbrack \overrightarrow{\mathbf{a}}\ \overrightarrow{\mathbf{b}}\ \overrightarrow{\mathbf{c}} \right\rbrack - \left\lbrack \overrightarrow{\mathbf{b}}\ \overrightarrow{\mathbf{c}}\ \overrightarrow{\mathbf{a}} \right\rbrack = 0$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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