(a)
Given volume of parallelopiped
$\left\lbrack \overrightarrow{\mathbf{a}}\ \overrightarrow{\mathbf{b}}\ \overrightarrow{\mathbf{c}} \right\rbrack = 40$
$\therefore$ Volume of parallelopiped
$= \left\lbrack \overrightarrow{\mathbf{b}} + \overrightarrow{\mathbf{c}}\ \overrightarrow{\mathbf{c}} + \overrightarrow{\mathbf{a}}\ \overrightarrow{\mathbf{a}} + \overrightarrow{\mathbf{b}} \right\rbrack = 2\left\lbrack \overrightarrow{\mathbf{a}}\ \overrightarrow{\mathbf{b}}\ \overrightarrow{\mathbf{c}} \right\rbrack$
$= 2 \times 40 = 80\ cu\ units$