Q. Let $ABCDEF$ be a regular hexagon and $\overrightarrow{\mathbf{AB}}\mathbf{=}\overrightarrow{\mathbf{a}}\mathbf{,\ }\overrightarrow{\mathbf{BC}}\mathbf{=}\overrightarrow{\mathbf{b}}\mathbf{,\ }\overrightarrow{\mathbf{CD}}\mathbf{=}\overrightarrow{\mathbf{c}}$, then $\overrightarrow{\mathbf{AE}}$ is equal to
A) $\overrightarrow{\mathbf{a}}\mathbf{+}\overrightarrow{\mathbf{b}}\mathbf{+}\overrightarrow{\mathbf{c}}$
B) $\overrightarrow{\mathbf{b}}\mathbf{+}\overrightarrow{\mathbf{c}}$
C) $\overrightarrow{\mathbf{a}}\mathbf{+}\overrightarrow{\mathbf{b}}$
D) $\overrightarrow{\mathbf{a}}\mathbf{+}\overrightarrow{\mathbf{c}}$
Explanation
The correct answer is Option B: $\overrightarrow{\mathbf{b}}\mathbf{+}\overrightarrow{\mathbf{c}}$.
A detailed explanation for this question is being prepared.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.