Q. If $\overrightarrow{\mathbf{a}} \bullet \widehat{\dot{\mathbf{i}}} = 4$ then $\left( \overrightarrow{\mathbf{a}} \times \widehat{\dot{\mathbf{j}}} \right) \bullet (2\widehat{\dot{\mathbf{j}}} - 3\widehat{\mathbf{k}})$ is equal to

A) 12
B) 2
C) 0
D) $- 12$
Explanation

(d)
$\left( \overrightarrow{\mathbf{a}} \times \widehat{\dot{\mathbf{j}}} \right) \bullet \left( 2\widehat{\dot{\mathbf{j}}} - 3\widehat{\mathbf{k}} \right) = \overrightarrow{\mathbf{a}} \bullet \left\{ \widehat{\dot{\mathbf{j}}} \times \left( 2\widehat{\dot{\mathbf{j}}} - 3\widehat{\mathbf{k}} \right) \right\}$
$= \overrightarrow{\mathbf{a}} \bullet \left\{ - 3\left( \widehat{\dot{\mathbf{j}}} \times \widehat{\mathbf{k}} \right) \right\} = - 3\left( \overrightarrow{\mathbf{a}} \bullet \widehat{\dot{\mathbf{i}}} \right)$
$= - 12$ $\lbrack\because\overrightarrow{\mathbf{a}} \bullet \widehat{\dot{\mathbf{i}}} = 4,$ given]

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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