Q. The value of $\widehat{\dot{\mathbf{i}}} \times \left( \widehat{\dot{\mathbf{j}}} \times \widehat{\mathbf{k}} \right) + \widehat{\dot{\mathbf{j}}} \times \left( \widehat{\mathbf{k}} \times \widehat{\dot{\mathbf{i}}} \right) + \widehat{\mathbf{k}} \times (\widehat{\dot{\mathbf{i}}} \times \widehat{\dot{\mathbf{j}}})$ is

A) $\overrightarrow{\mathbf{0}}$
B) $\widehat{\dot{\mathbf{i}}}$
C) $\widehat{\dot{\mathbf{j}}}$
D) $\widehat{\mathbf{k}}$
Explanation

(a)
Now, $\widehat{\dot{\mathbf{i}}} \times \left( \widehat{\dot{\mathbf{j}}} \times \widehat{\mathbf{k}} \right) = \widehat{\dot{\mathbf{i}}} \times \widehat{\dot{\mathbf{i}}} = \overrightarrow{\mathbf{0}}$
$\widehat{\dot{\mathbf{j}}} \times \left( \widehat{\mathbf{k}} \times \widehat{\dot{\mathbf{i}}} \right) = \widehat{\dot{\mathbf{j}}} \times \widehat{\dot{\mathbf{j}}} = \overrightarrow{\mathbf{0}}$
$and\ \widehat{\mathbf{k}} \times \left( \widehat{\dot{\mathbf{i}}} \times \widehat{\dot{\mathbf{j}}} \right)\widehat{\mathbf{k}} \times \widehat{\mathbf{k}} = \overrightarrow{\mathbf{0}}$
$\therefore\ \widehat{\dot{\mathbf{i}}} \times \left( \widehat{\dot{\mathbf{j}}} \times \widehat{\mathbf{k}} \right) + \widehat{\dot{\mathbf{j}}} \times \left( \widehat{\mathbf{k}} \times \widehat{\dot{\mathbf{i}}} \right) + \widehat{\mathbf{k}} \times \left( \widehat{\dot{\mathbf{i}}} \times \widehat{\dot{\mathbf{j}}} \right) = \overrightarrow{\mathbf{0}}$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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