Q. If $2\widehat{\dot{\mathbf{i}}} + 4\widehat{\dot{\mathbf{j}}} - 5\widehat{\mathbf{k}}$ and $\widehat{\dot{\mathbf{i}}} + 2\widehat{\dot{\mathbf{j}}} + 3\widehat{\mathbf{k}}$ are adjacent side of a parallelogram, then the lengths of its diagonals are

A) $7,\sqrt{69}$
B) $6,\sqrt{59}$
C) $5,\sqrt{65}$
D) $5,\sqrt{55}$
Explanation

(a)
Let $\overrightarrow{\mathbf{a}} = 2\widehat{\dot{\mathbf{i}}} + 4\widehat{\dot{\mathbf{j}}} - 5\widehat{\mathbf{k}}$, $\overrightarrow{\mathbf{b}} = \widehat{\dot{\mathbf{i}}} + 2\widehat{\dot{\mathbf{j}}} + 3\widehat{\mathbf{k}}$
First diagonal, $\overrightarrow{\mathbf{a}} + \overrightarrow{\mathbf{b}} = 3\widehat{\dot{\mathbf{i}}} + 6\widehat{\dot{\mathbf{j}}} - 2\widehat{\mathbf{k}}$
$\Longrightarrow \left| \overrightarrow{\mathbf{a}} + \overrightarrow{\mathbf{b}} \right| = 7$
Second diagonal, $\overrightarrow{\mathbf{a}} - \overrightarrow{\mathbf{b}} = \widehat{\dot{\mathbf{i}}} + 2\widehat{\dot{\mathbf{j}}} - 8\widehat{\mathbf{k}}$
$\Longrightarrow \left| \overrightarrow{\mathbf{a}} - \overrightarrow{\mathbf{b}} \right| = \sqrt{69}$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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