Explanation

(c)
Given, constraints are
$x \geq 0,\ y \geq 0,\ x + y \leq 12,\ 2x + y \leq 20$
The feasible region is $OABCO$
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At $O(0,\ 0),\ z = 100(0) + 6(0) = 0$
At $A(10,\ 0),z = 10(10) + 6(0) = 100$
At $B(8,\ 4),\ z = 10(8) + 6(4) = 104$
At $C(0,\ 12),\ z = 10(0) + 6(12) = 72$
Hence, maximum value of $z$ is 104