Q. The minimum value of $z = 5x - 4y$ subject to constraints $x + y \leq 10,\ y \leq 4;x,\ y > 0$ will be at the point
A) (10, 4)
B) (-10, 4)
C) (6, 4)
D) (0, 4)
Explanation
(d)
$\because\ \ \ QRSOQ$ is the feasible region
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and $z = 5x - 4y$
At $Q(0,\ 4),\ z = - 16$
At $R(6,4),\ z = 14$
At $O(0,\ 0),\ z = 0$
At $S(10,\ 0),\ z = 50$
$\therefore$ Minimum value is -16 which is attained at point (0, 4)
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.