(d)
Feasible region is $ABCA$
[image:12_image8.jpeg]
and $z = 7x - 8y$
now, At $A(0,\ 5);\ \ \ \ z = 7(0) - 8(5) = - 40$
at $B(15,\ 5);\ \ \ \ z = 7(15) - 8(5) = 65$
at $C(0,\ 20);\ \ \ z = 7(0) - 8(20) = - 160$
$\therefore$ The minimum value of $z$ is attained at point (0, 20)