Q. The length of projection of the line segment joining the points $(1,\ 0,\ - 1)$ and $( - 1,\ 2,\ 2)$ on the plane $x + 3y - 5\mathcal{z} = 6$, is equal to

A) 2
B) $\sqrt{\frac{271}{53}}$
C) $\sqrt{\frac{472}{31}}$
D) $\sqrt{\frac{474}{35}}$
Explanation

(d)
Let $A(1,\ 0,\ - 1),\ B( - 1;2,\ 2)$
Direction ratios of segment $AB$ are $< 2,\ - 2,\ - 3 >$
$\cos\theta = \frac{\left| 2 \times 1 + 3( - 2) - 5( - 3) \right|}{\sqrt{1 + 9 + 25}\sqrt{4 + 4 + 9}} = \frac{11}{\sqrt{17}\sqrt{35}} = \frac{11}{\sqrt{595}}$
Length of projection $= (AB)\sin\theta$
$= \sqrt{(2)^{2} + (2)^{2} + (3)^{2}} \times \sqrt{1 - \frac{121}{595}}$
$= \sqrt{17}\frac{\sqrt{474}}{\sqrt{17}\sqrt{35}} = \sqrt{\frac{474}{35}}\ \ units$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.