Moment of inertia of a disc of mass $M$ and radius '$R$' about any of its diameter is $\frac{MR^2}{4}$. The moment of inertia of this disc about an axis normal to the disc and passing through a point on its edge will be, $\frac{x}{2}MR^2$. The value of $x$ is ______.

Question

Dr. Abubacker · Accepted Answer

The correct numerical answer is 3.

Q. Moment of inertia of a disc of mass $M$ and radius '$R$' about any of its diameter is $\frac{MR^2}{4}$. The moment of inertia of this disc about an axis normal to the disc and passing through a point on its edge will be, $\frac{x}{2}MR^2$. The value of $x$ is ______.

Explanation

Reviewed by Dr. Abubacker

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