Nucleus a having $Z=17$ and equal number of protons and neutrons has $1.2\ \mathrm{MeV}$ binding energy per nucleon. Another nucleus $B$ of $Z=12$ has total $26$ nucleons and $1.8\ \mathrm{MeV}$ binding energy per nucleons. The difference of binding energy of $B$ and $A$ will be ______ MeV.

Question

Dr. Abubacker · Accepted Answer

The correct numerical answer is 6.

Q. Nucleus a having $Z=17$ and equal number of protons and neutrons has $1.2\ \mathrm{MeV}$ binding energy per nucleon. Another nucleus $B$ of $Z=12$ has total $26$ nucleons and $1.8\ \mathrm{MeV}$ binding energy per nucleons. The difference of binding energy of $B$ and $A$ will be ______ MeV.

Explanation

Reviewed by Dr. Abubacker

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