Q. $1\times10^{-5}\ \mathrm{M\ AgNO_3}$ is added to $1\ \mathrm{L}$ of saturated solution of $\mathrm{AgBr}$. The conductivity of this solution at $298\ \mathrm{K}$ is _______ $\times10^{-8}\ \mathrm{S\ m^{-1}}$. [Given : $\mathrm{K_{sp}(AgBr)}=4.9\times10^{-13}$ at $298\ \mathrm{K}$ $\lambda^0_{\mathrm{Ag^+}}=6\times10^{-3}\ \mathrm{Sm^2\ \ mol^{-1}}$ $\lambda^0_{\mathrm{Br^-}}=8\times10^{-3}\ \mathrm{Sm^2\ \ mol^{-1}}$ $\lambda^0_{\mathrm{NO_3^-}}=7\times10^{-3}\ \mathrm{Sm^2\ \ mol^{-1}}$]

Numerical Question

This is a numerical-answer question. The correct answer is shown below.

Explanation

The correct numerical answer is 13039.

A detailed explanation for this question is being prepared.

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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