Q. The threshold frequency of metal is $f_0$. When the light of frequency $2f_0$ is incident on the metal plate, the maximum velocity of photoelectron is $v_1$. When the frequency of incident radiation is increased to $5f_0$. the maximum velocity of photoelectrons emitted is $v_2$. The ratio of $v_1$ to $v_2$ is:
A) $\frac{v_1}{v_2}=\frac{1}{2}$
B) $\frac{v_1}{v_2}=\frac{1}{8}$
C) $\frac{v_1}{v_2}=\frac{1}{16}$
D) $\frac{v_1}{v_2}=\frac{1}{4}$
Explanation
The correct answer is Option A: $\frac{v_1}{v_2}=\frac{1}{2}$.
A detailed explanation for this question is being prepared.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.