Q. The correct order of bond enthalpy $(\mathrm{kJ\ \ mol^{-1}})$ is:
A) $\mathrm{Si-Si > C-C > Sn-Sn > Ge-Ge}$
B) $\mathrm{Si-Si > C-C > Ge-Ge > Sn-Sn}$
C) $\mathrm{C-C > Si-Si > Sn-Sn > Ge-Ge}$
D) $\mathrm{C-C > Si-Si > Ge-Ge > Sn-Sn}$
Explanation
The correct answer is Option D: $\mathrm{C-C > Si-Si > Ge-Ge > Sn-Sn}$.
A detailed explanation for this question is being prepared.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.