Q. Let $P(x_0, y_0)$ be the point on the hyperbola $3x^2-4y^2=36$, which is nearest to the line $3x+2y=1$. Then $\sqrt{2}(y_0-x_0)$ is equal to :
A) $-3$
B) $9$
C) $-9$
D) $3$
Explanation
The correct answer is Option C: $-9$.
A detailed explanation for this question is being prepared.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.