Q. For the system of linear equations $ax+y+z=1, x+ay+z=1, x+y+az=\beta$, which one of the following statements is NOT correct?
A) It has infinitely many solutions if $\alpha=2$ and $\beta=-1$
B) It has no solution if $\alpha=-2$ and $\beta=1$
C) $x+y+z=\frac{3}{4}$ if $\alpha=2$ and $\beta=1$
D) It has infinitely many solutions if $\alpha=1$ and $\beta=1$
Explanation
The correct answer is Option A: It has infinitely many solutions if $\alpha=2$ and $\beta=-1$.
A detailed explanation for this question is being prepared.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.