Let $\alpha x=\exp\left(x^{\beta}y^{\gamma}\right)$ be the solution of the differential equation $2x^2ydy-(1-xy^2)dx=0$, $x0, y(2)=\sqrt{\log_e 2}$. Then $\alpha+\beta-\gamma$ equals :

Question

Let $\alpha x=\exp\left(x^{\beta}y^{\gamma}\right)$ be the solution of the differential equation $2x^2ydy-(1-xy^2)dx=0$, $x>0, y(2)=\sqrt{\log_e 2}$. Then $\alpha+\beta-\gamma$ equals :

Dr. Abubacker · Accepted Answer

The correct answer is Option A: $1$.

Q. Let $\alpha x=\exp\left(x^{\beta}y^{\gamma}\right)$ be the solution of the differential equation $2x^2ydy-(1-xy^2)dx=0$, $x>0, y(2)=\sqrt{\log_e 2}$. Then $\alpha+\beta-\gamma$ equals :

Explanation

Reviewed by Dr. Abubacker

Want to attempt the full paper?