Q. A microscope has an objective of focal length 2 cm, eyepiece of focal length 4 cm and the tube length of 40 cm. If the distance of distinct vision of eye is 25 cm, the magnification in the microscope is
A) 100
B) 125
C) 150
D) 250
Explanation
[Solution by Claude - not from source] Using the standard approximation $m=\frac{L}{f_o}\cdot\frac{D}{f_e}=\frac{40}{2}\times\frac{25}{4}=125$. Answer (2).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.