A ball of mass 0.5 kg is dropped from a height of 40 m. The ball hits the ground and rises to a height of 10 m. The impulse imparted to the ball during its collision with the ground is (Take $g = 9.8$ $m/s^2$)

Question

Dr. Abubacker · Accepted Answer

[Solution by Claude - not from source] Speed before impact $=\sqrt{2	imes9.8	imes40}=28$ m/s; speed after $=\sqrt{2	imes9.8	imes10}=14$ m/s (reversed). Impulse $=0.5(14+28)=21$ Ns. Answer (1).

Q. A ball of mass 0.5 kg is dropped from a height of 40 m. The ball hits the ground and rises to a height of 10 m. The impulse imparted to the ball during its collision with the ground is (Take $g = 9.8$ $m/s^2$)

Explanation

Reviewed by Dr. Abubacker

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