Q. An oxygen cylinder of volume 30 litre has 18.20 moles of oxygen. After some oxygen is withdrawn from the cylinder, its gauge pressure drops to 11 atmospheric pressure at temperature $27^\circ$C. The mass of the oxygen withdrawn from the cylinder is nearly equal to : [Given, $R=\frac{100}{12}\,J\,mol^{-1}K^{-1}$, and molecular mass of $O_2 = 32$, 1 atm pressure $= 1.01 \times 10^5\,N/m^2$]

A) 0.125 kg
B) 0.144 kg
C) 0.116 kg
D) 0.156 kg
Explanation

[Solution by Claude - not from source] Absolute pressure $=11+1=12$ atm $=1.212\times10^6$ Pa. $n_f=\frac{PV}{RT}=\frac{1.212\times10^6\times30\times10^{-3}}{(100/12)\times300}\approx14.54$ mol. Withdrawn $=18.20-14.54\approx3.66$ mol $\approx0.117$ kg, closest to 0.116 kg. Answer (3).

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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