[Solution by Claude - not from source] Bus spacing $vT$. Same direction: $vT=(v-60)\times30$; opposite: $vT=(v+60)\times10$ (times in min, speeds per min-consistent). So $3(v-60)=v+60\Rightarrow v=120$ km/h, and $T=\frac{(180)(10)}{120}=15$ min. Answer (4).