Q. Consider the diameter of a spherical object being measured with the help of a Vernier callipers. Suppose its 10 Vernier Scale Divisions (V.S.D.) are equal to its 9 Main Scale Divisions (M.S.D.). The least division in the M.S. is 0.1 cm and the zero of V.S. is at $x = 0.1$ cm when the jaws of Vernier callipers are closed. If the main scale reading for the diameter is $M = 5$ cm and the number of coinciding vernier division is 8, the measured diameter after zero error correction, is:
A) 5.18 cm
B) 5.08 cm
C) 4.98 cm
D) 5.00 cm
Explanation
[Solution by Claude - not from source] Least count $=0.1/10=0.01$ cm. Reading $=5+8\times0.01=5.08$ cm. Zero error $=+0.1$ cm, so corrected $=5.08-0.1=4.98$ cm. Answer (3).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.