Q. A container has two chambers of volumes $V_1 = 2$ litres and $V_2 = 3$ litres separated by a partition made of a thermal insulator. The chambers contains $n_1 = 5$ and $n_2 = 4$ moles of ideal gas at pressures $p_1 = 1$ atm and $p_2 = 2$ atm, respectively. When the partition is removed, the mixture attains an equilibrium pressure of:
A) 1.3 atm
B) 1.6 atm
C) 1.4 atm
D) 1.8 atm
Explanation
[Solution by Claude - not from source] No heat exchange or work, so total internal energy is conserved: $\frac{f}{2}(p_1V_1+p_2V_2)=\frac f2 P(V_1+V_2)$. $P=\frac{1\times2+2\times3}{5}=1.6$ atm. Answer (2).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.