Q.
Two identical point masses $P$ and $Q$, suspended from two separate massless springs of spring constants $k_1$ and $k_2$ respectively, oscillate vertically. If their maximum speeds are the same, the ratio ($A_Q/A_P$) of the amplitude $A_Q$ of mass $Q$ to the amplitude $A_P$ of mass $P$ is:
A) $\frac{k_2}{k_1}$
B) $\frac{k_1}{k_2}$
C) $\sqrt{\frac{k_2}{k_1}}$
D) $\sqrt{\frac{k_1}{k_2}}$
Explanation
[Solution by Claude - not from source] $v_{max}=A\omega=A\sqrt{k/m}$. Equal $m$ and equal $v_{max}$: $A_P\sqrt{k_1}=A_Q\sqrt{k_2}\Rightarrow\frac{A_Q}{A_P}=\sqrt{\frac{k_1}{k_2}}$. Answer (4).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.