Q.
A pipe open at both ends has a fundamental frequency $f$ in air. The pipe is now dipped vertically in a water drum to half of its length. The fundamental frequency of the air column is now equal to:
A) $\frac{f}{2}$
B) $f$
C) $\frac{3f}{2}$
D) $2f$
Explanation
[Solution by Claude - not from source] Open pipe: $f=\frac{v}{2L}$. Dipped to half length it becomes a closed pipe of length $L/2$: $f'=\frac{v}{4(L/2)}=\frac{v}{2L}=f$. Answer (2).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.