Q. The ratio of the wavelengths of the light absorbed by a Hydrogen atom when it undergoes $n = 2 \rightarrow n = 3$ and $n = 4 \rightarrow n = 6$ transitions, respectively, is
A) $\frac{1}{36}$
B) $\frac{1}{16}$
C) $\frac{1}{9}$
D) $\frac{1}{4}$
Explanation
[Solution by Claude - not from source] $\frac1\lambda\propto\frac1{n_1^2}-\frac1{n_2^2}$. For 2→3: $\frac5{36}$; for 4→6: $\frac{5}{144}$. $\frac{\lambda_1}{\lambda_2}=\frac{5/144}{5/36}=\frac14$. Answer (4).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.