Q. Consider the following compounds: $\underline{K}O_2$, $H_2\underline{O}_2$ and $H_2\underline{S}O_4$ The oxidation states of the underlined elements in them are, respectively,
A) +1, –1, and +6
B) +2, –2, and +6
C) +1, –2, and +4
D) +4, –4, and +6
Explanation
[Solution by Claude - not from source] In $KO_2$, K is $+1$. In $H_2O_2$, O is $-1$. In $H_2SO_4$, S is $+6$. Answer (1).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.