If the half-life ($t_{1/2}$) for a first order reaction is 1 minute, then the time required for 99.9% completion of the reaction is closet to:

Question

Dr. Abubacker · Accepted Answer

[Solution by Claude - not from source] $t=\frac{2.303}{k}\log\frac{100}{0.1}=\frac{2.303	imes3}{0.693}\approx10$ min (about 10 half-lives, as $2^{10}\approx1000$). Answer (4).

Q. If the half-life ($t_{1/2}$) for a first order reaction is 1 minute, then the time required for 99.9% completion of the reaction is closet to:

Explanation

Reviewed by Dr. Abubacker

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