If the molar conductivity ($\Lambda_m$) of a 0.050 mol L$^{-1}$ solution of a monobasic weak acid is 90 S cm$^2$ mol$^{-1}$, its extent (degree) of dissociation will be [Assume $\Lambda^\circ_+ = 349.6$ S cm$^2$ mol$^{-1}$ and $\Lambda^\circ_- = 50.4$ S cm$^2$ mol$^{-1}$]

Question

Dr. Abubacker · Accepted Answer

[Solution by Claude - not from source] $\Lambda^\circ_m=349.6+50.4=400$. $\alpha=\frac{\Lambda_m}{\Lambda^\circ_m}=\frac{90}{400}=0.225$. Answer (3).

Q. If the molar conductivity ($\Lambda_m$) of a 0.050 mol L$^{-1}$ solution of a monobasic weak acid is 90 S cm$^2$ mol$^{-1}$, its extent (degree) of dissociation will be [Assume $\Lambda^\circ_+ = 349.6$ S cm$^2$ mol$^{-1}$ and $\Lambda^\circ_- = 50.4$ S cm$^2$ mol$^{-1}$]

Explanation

Reviewed by Dr. Abubacker

Want to attempt the full paper?